(3x^2-17x-28)/(3x-4)

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Solution for (3x^2-17x-28)/(3x-4) equation: 


D( x )

3*x-4 = 0

3*x-4 = 0

3*x-4 = 0

3*x-4 = 0 // + 4

3*x = 4 // : 3

x = 4/3

x in (-oo:4/3) U (4/3:+oo)

(3*x^2-(17*x)-28)/(3*x-4) = 0

(3*x^2-17*x-28)/(3*x-4) = 0

3*x^2-17*x-28 = 0

3*x^2-17*x-28 = 0

DELTA = (-17)^2-(-28*3*4)

DELTA = 625

DELTA > 0

x = (625^(1/2)+17)/(2*3) or x = (17-625^(1/2))/(2*3)

x = 7 or x = -4/3

(x+4/3)*(x-7) = 0

((x+4/3)*(x-7))/(3*x-4) = 0

( x+4/3 )

x+4/3 = 0 // - 4/3

x = -4/3

( x-7 )

x-7 = 0 // + 7

x = 7

x in { -4/3, 7 }

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